The area of the triangle formed the points (1, 1), (2, 2) and (-1, 2) is
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Answer:
AB
=(1,1,−2)
AC
=(2,−1,−1)
n
=
AB
×
AC
=
∣
∣
∣
∣
∣
∣
∣
∣
i
^
1
2
j
^
1
−1
k
^
−2
−1
∣
∣
∣
∣
∣
∣
∣
∣
=−3
i
^
−3
j
^
−3
k
^
Area of Δ=
2
1
∣
n
∣
=
2
3
3
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