Question

the area of the triangle is 72 CM square and the Three attitudes measures 24 cm 18 cm and 16 cm find the perimeter of the triangle

Answer 1

Answer:

1)first,h=24cm

area of triangle =1/2*b*h

72=1/2*b*24

72/24=1/2*b

3=1/2*b

3*2=b

b=6cm

2)second,h=18cm

area of triangle =1/2*b*h

72=1/2*b*18

72/18=1/2*b

4=1/2*b

b=4*2

b=8cm

3)h=16

area of triangle =1/2*b*h

72=1/2*b*16

72/16*2=b

b=9cm

perimeter of triangle =sum of all sides

perimeter =b1+b2+b3

perimeter =6+8+9

perimeter of triangle =23cm

IT WILL HELP YOU.

Answer 2

AE=24cm

BF=18cm

CD=16cm

.

.

½×AE×BC=72

½×24×BC=72

BC=6cm

.

.

½×BF×AC=72

½×18×AC=72

AC=8cm

.

.

½×CD×AB=72

½×16×AB= 72

AB=9cm

.

.

perimeter= AB+ BC + AC

= 6+8+9=23cm