Question

The area of the triangle whose sides are 42 cm, 34 cm and 20 cm in length isin length​

Answer 1

Answer:

area of the triangle having sides a, b, c

area=√(s*(s-a)*(s-b)*(s-c))

where s=(a+b+c)/2

so value of s=(42+34+20)/2

s=(96/2)=48

area of triangle=√(48*(48-42)*(48-34)*(48-20))

=√(48*6*14*28)

=√(112896)

area of triangle=336 square cm