Question

The area of the triangle whose sides are 9 cm, 10 cm, and 11 cm, equals tothe area of the triangle whose sides are 9 cm, 10 cm, and 11 cm, equals to

Answer 1

Answer:

The area of triangle will be 30sqrt2 square cm

Step-by-step explanation:

We have,

a=9,b=10,c=11

Semi peremeter s=a+b+c/2

s=9+10+11/2=30/2=15

Apply hero's formula

Area of triangle =sqrt s(s-a) (s-b) (s-c)

=sqrt 15(15-9)(15-10)(15-11)

=sqrt15*6*5*4

=sqrt1800

=30sqrt2 square cm