Question

The area of the triangle whose vertices are (0,0), (a,0) and (0,b) is
1 point
ab
1/2ab
a+b
a^2+b^2​

Answer 1

ANSWER

The area of a triangle formed by joining the points (x

1

,y

1

), (x

2

,y

2

) and (x

3

,y

3

) is

A=

2

1

∣y

1

(x

2

−x

3

)+y

2

(x

3

−x

1

)+y

3

(x

1

−x

2

)∣

Therefore, the area of a triangle formed by joining the points (0,0), (0,a) and (b,0) is:

A=

2

1

∣0(0−b)+a(b−0)+0(0−0)∣=

2

1

(0+ab)

2

ab

Hence, the area of the triangle is

2ab .

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