Question

the area of the triangle whose vertices are (1,-1), (0,6), and (0,-6) is...
1. 6 sq. unit
2. -6 sq.unit
3. 12 sq. unit
4. -12 sq. unit



Guys solve it plss...
fast....​

Answer 1

Answer:

Let us assume ABC is a triangle whose vertices are A(6, 3), B(-3, 5) and C(4, -2)

So,

Area of ∆ABC = 1/2[x1(y2 – y3) + (y3 – y1)x2 + x3(y1 – y2)]

= 1/2[6(5 + 2) + (-3)(-2 – 3) + 4(3 – 5)]

= 1/2[6(5 + 2) + (-3)(-2 – 3) + 4(3 – 5)]

= 1/2[42 + 15 – 8]

= 1/2 * 49

carry out this procedure and you will get the result

= 49/2 sq.unit

Answer 2

Dii aapko warning mil raha hai?