Question

the area of the triangle whose vertices are (a a) (a + 1 a + 1) and (a + 2 a) is ​

Answer 1

area of a triangle =2/2 × base × height

Answer 2

The area of triangle is 1 square units.

Step-by-step explanation:

If three vertices of a triangle are given, then the area of triangle is

$Area=\frac{1}{2}|x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)|$

The given vertices of triangle are (a,a) (a + 1,a + 1) and (a + 2, a).

Using the above formula the area of triangle is

$Area=\frac{1}{2}|a((a+1)-(a))+(a+1)(a-(a))+(a+2)(a-(a+1))|$

$Area=\frac{1}{2}|a(1)+(a+1)(0)+(a+2)(-1)|$

$Area=\frac{1}{2}|a+0-a-2|$

$Area=\frac{1}{2}|-2|$

Applying modulus we get

$Area=\frac{1}{2}(2)$

$Area=1$

Therefore, the area of triangle is 1 square units.

#Learn more

Find the area of a triangle whose vertices are (3,2)(-2-3) (2,3).

https://brainly.in/question/6626034