Question

the area of the triangle with vertices (3, 0) , (7, 0) and (8, 4) is _________ square unit's​

Answer 1

Answer:

8 sq. units

Step-by-step explanation:

ar. of triangle = 1/2 | x1(y2-y3) + x2(y3-y1) + x3(y1-y2) |

= 1/2 | 3(0-4) + 7(4-0) + 8(0-0) |

= 1/2 | 3(-4) + 7(4) + 8(0) |

= 1/2 | -12 + 28 |

= 1/2 | 16 |

= 16/2

= 8 sq. units

Hope this helps... :-)