The area of the triangle with vertices (3, 0), (7, 0) and (9, 2) is square units.
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Explanation:
The area of the ΔABC with vertices
A(x1,y1)=(3,0),B(x2,y2)=(7,0) & C(x3,y3)=(8,4)is
Ar.ΔABC=21[x1(y2−y3)+x2(y3−y1)+x3(y1−y2)]
=21{3(0−4)+7(4−0)+8(0−0)} sq.units =8 sq. units.
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Answer:
The area of the ΔABC with vertices
A(x1,y1)=(3,0),B(x2,y2)=(7,0) & C(x3,y3)=(8,4)is
Ar.ΔABC=21[x1(y2−y3)+x2(y3−y1)+x3(y1−y2)]
=21{3(0−4)+7(4−0)+8(0−0)} sq.units =8 sq. units.
Explanation:
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