Question

The area of the two adjacent walls of a room is 72 m². If the length of the room is twice its width and the height is 4 m, then find the area of the floor. [HINT: Area of the 2 adjacent walls = (length+breadth) * height]

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Answer 1

Answer:

Let the width of the room be w m

Then, the length of the room

= twice its breadth

= 2w m

Length of the room = 2w m

Given that

Height of the room = 4 m

We know that

The area of a two adjacent walls of the room = (length +breadth)×height sq.units

Area of the two adjacent walls of the given room

=> A = (2w+w)×4 m²

=> A = 3w×4 m²

=> A = 12w m²

According to the given problem

The area of the two adjacent walls of a room

= 72 m²

=> 12w = 72

=> w = 72/12

=> w = 6 m

Width of the room = 6 m

Length of the room = 2w = 2×6 = 12 m

Now

Area of the floor of a room = length×breadth sq.units

Area of the floor of the given room

= 12×6 = 72 m²

Answer:-

Area of the floor of the given room

= 72 m²

Check :-

If length = 12 m width = 6 m and height = 4 m then

The area of the two adjacent walls of a room

=> (12+6)×4 m²

=> 18×4 m²

=> 72 m²

Verified the given relations in the given problem.

Used formulae:-

→ The area of a two adjacent walls of the room A = (length +breadth)×height

sq. units

→ Area of the floor of a room = length×breadth sq.units

Points to know:-

→ Area of the four walls of a room is 2h(l+b) sq.units

l = length

b = breadth / width

h = height

Step-by-step explanation:

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I am Sandhya and I am 10

I live in kerala