The area of traingle abd is 10sqcm and area if traingle adc is 12sqcm (a) find bd:dc (b) if bd=5cm,then find dc
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Answer:
Ans. bd : dc = 5: 6
Step-by-step explanation:
Area of triangle adb = h X b1 / 2
10 = h x 5 / 2
h = 4cm
Area of triangle adc = h X b2 / 2
12 = 4 X b2 / 2
cd / b2 = 24 / 4
cd /b2 = 6 cm
Ans. bd : dc = 5: 6
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