Question

the area of trapezium 300 m2 square to the perpendicular distance between the two parallel side is 15 mif the differences of The parallel sides is 16 m find the length of the parallel sides

Answer 1

hey
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•area of trapezium=1/2×(sum of || sides) × perpendicular distance

given
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•area=300m^2
•perpendicular distance =15m

let the parallel side be x
another be x-16

now, 1/2×(x+x-16)×15=300
15/2(2x-16)=300
15/2×2x-16×15/2=300
15x-120=300
15x=300+120
15x=420
x=28

•first parallel side=28m
•second parallel side =28-16=12m

hope helped
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Answer 2

Given :

Area of the trapezium = 300 m²

Perpendicular distance (Height) = 15 m

Let the smaller side= x

Now the bigger side = x+16

½× (x+x+16)×15 = 300

½× (2x+16) = 300/15

½×(2x+16) = 20

2x+16 = 40

2x = 24

x= 24/2 = 12 m

Now, x+16= 12+16 =28 m

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