Question

the area of trapezium in 12 square metre.If its height is 8.If one of the parallel side is smaller than the other by 4 metre.Find its two parallel sides​

Answer 1

Step-by-step explanation:

Area of trapezium

$\frac{1}{2} \times \:(sum \: of \: parallel \: sides) \times height$

$12 = \frac{1}{2} \times (x + x - 4) \times 8$

$24 = 8(2x - 4)$

$3 = 2x - 4 \\ 2x = 7 \\ x = 3.5$

Question is incorrect

as other side comes out in negative value.

Answer 2

Answer:

The 2 parallel sides are 98m and 94m

Step-by-step explanation:

1.Given = Area of Trapezium=12 m square,Height =8 m, let one parallel side be =X . then according to the condition second parallel line =x-4 .

2.so Area of the Trapezium =a+b__

2×height

3. so 12= A+B

2×8

4. so 12=A+B

16

5.so 16×12

x+x-4

6.so 192 =0

2x-4

7. so 192 = 2x-4

8. so 192+4=2x

9.so 196=2x

10. so 196 = X

2

11.so x=98

12. so x-4 =98-4=94

13. proof = AREA OF THE TRAPEZIUM = A+B

2×H

14. 98+94

2×8

15. 192

16

16. 12 m square