Question

The area of trapezium in whose parallel sides are 10 cm and 12 cm and distance between them is 4 cm is​

Answer 1

Step-by-step explanation:

Area of trapezium=

$\frac{1}{2} \times sum \: of \: parallel \: sides \times distance \: between \: them$

$\frac{1}{2} \times (10 + 12) \times 4$

$44 {cm}^{2}$

Answer 2

Given :

⬤ Parallel Sides of Trapezium are 10 cm and 12 cm .

⬤ Distance between them is 4 cm .

To Find :

⬤ Area of Trapezium .

Formula Used :

$\sf[\:{Area\:of\:Trapezium=\dfrac{1}{2}\times{(Sum\:of\:Parallel\:Sides)}\times{h}}\:]$

Solution :

According to the Formula :

1/2 × (Sum of Parallel Sides) × h

1/2 × (10 + 12) × 4

1/2 × 22 × 4

11 × 4

44

Therefore , The Area of the Trapezium is 44 cm² .

═════════════════════════

Related Formulas :

• Area of Trapezium = ½ × (Sum of Parallel Sides) × h
• Area of Rectangle = l × b
• Area of Square = Side × Side
• Area of Parallelogram = b × h
• Area of Triangle = 1/2 × b × h
• Area of Circle = πr²

═════════════════════════