Math, asked by ashasaraf09, 11 months ago

the area of trapezium is 100cm and it's height is 8cm .Find the length of the 2 parallel sides of one side is longer than the other by 5cm​

Answers

Answered by hiru43
6

Step-by-step explanation:

Area of trapezium = 1/2 h(a+b)

Given h = 8 let us take a and b as x ,x+5

so, 1/2 × 8 × x+x+5 = 100

4 × 2x+5 = 100

2x+5 = 25. (100/4)

2x. = 25 -5

2x = 20

x = 10

so the values of parallel sides are

x = 10 cm

x+5= 15 cm

Answered by kp22227
1

Step-by-step explanation:

Area of trapezium = 1/2 × height × (sum of parallel side)

Given height = 8 let us take a( 1st parallel side), and b(2nd parallel side) as x , x+5

so, 1/2 x 8 x x+x+5 = 100

4 x 2x+5 = 100

2x+5 = 25. (100/4)

2x. = 25-5

2x = 20

x = 10

26

so the values of parallel sides are

x (1st side) = 10 cm

x+5 (2Nd side) = 15 cm

Ans= So, the length of 1st parallel side is 10cm

and the 2nd parallel side length is 15cm

THANKS

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