Question

the area of trapezium is 105 cm² and its height is 7 cm . if one of the parallel sides is longer than the other by 6 cm then find the lengths of two parallel sides .​

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Answer 1

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Answer 2

QuestioN :

The area of trapezium is 105 cm² and its height is 7 cm . if one of the parallel sides is longer than the other by 6 cm then find the lengths of two parallel sides .​

GiveN :

• The area of trapezium is 105 cm²

• It's height is 7 cm.

• If one of the parallel sides is longer than the other by 6 cm.

To FiNd :

• Find the length of two parallel sides.

ANswer :

❖First Side is 5 cm.

❖Second side is x + 6 = 11 cm

SolutioN :

Let the first side be " x "

The the second side is 6 more then other = x + 6

As we know that:-

$Area\:of \:trapezium\:=\frac{a+b}{2} *h$

Substituting Values:-

$=105=\frac{x+x+6}{2} *7$

$=105*2=(x^{2} +6)7$

$=210=7x^{2} +42$

$=7x^{2} =210-42$

$=7x^{2} =168$

$=x^{2}= \frac{168}{7}$

$=x=\sqrt[]{24}$

$=x=5$

∴Hence,

❖First Side is 5 cm.  

❖Second side is x + 6 = 11 cm