the area of trapezium is 1080 cm2.if the lengths of its parallel sides are 55.6 cm and 34.4 cm, find the distance between them.
Answers
Area of trapezium = 1/2 × (a+b) × h
*a and b are the parallel lengths
Now we are going to find the distance, which is height (also known as 'h').
First, substitute the given values into the equation.
1080 = 1/2 × (55.6 + 34.4) × h
Move the 1/2 over to 1080 and divide.
1080 ÷ 1/2 = (55.6 + 34.4) × h
2160 = (55.6 + 34.4) × h
Add the numbers in the brackets.
2160 = 90 × h
Move 90 over to 2160 and divide.
2160 ÷ 90 = h
24 = h
Therefore, the distance (height) is 24cm.
Given,
- Area of the trapezium = 1080 cm²
- length of its parallel sides = 55.6 cm and 34.4 cm
To find,
- We have to find the distance between them.
Solution,
We can simply find the distance between the parallel sides of the trapezium by using the following formula:
Area of the Trapezium = 1/2 * (sum of parallel sides) * height
Area of the trapezium = 1080 cm²
Sum of the parallel sides = 55.6 + 34.4
= 90 cm
Substituting the given values in the above formula of area of a trapezium, we get
1080 = 1/2 * 90 * distance between them
1080 = 45 * distance between them
1080/45 = distance between them
24 cm = distance between them
Hence, the area of the trapezium is 1080 cm². If the lengths of its parallel sides are 55.6 cm and 34.4 cm, then the distance between them is 24 cm.