Question

The area of trapezium is 1440cm². if the length of its parallel sides are 54.6cm and 5.47cm, find the distance between them.
(class 8 CBSE chapter area of polygon) subject maths​

Answer 1

Answer:

47.5 cm

Step-by-step explanation:

area of trapezium = 1/2*h*(sum of parallel sides)

sum of parallel sides = 54.6+5.47 = 60.07cm

so , area of trapezium = 1/2*h*(sum of parallel sides)

>> 1440 = 1/2*h*60.07

>> h = 1440*2/60.07

>> h = 47.446 = 47.5 cm answer

distance between parallel sides = h 47.5 cm.

Plz mark me as brainlist answer.

Answer 2

Answer:

Draw perpendicular from F and E i.e. FB and EC

then FE=BC and triangle FAB and ECD are two right triangles

Step-by-step explanation:

Area of a trapezium ADEF = (½ x AB x FB) + (BC x FB) + (½ x CD x EC)

= (¹/₂ × AB × h) + (BC × h) + (¹/₂ × CD × h)

= ¹/₂ × h × (AB + 2BC + CD)

= 1/2×h×(AB+BC+FE+CD)

= ¹/₂ × h × (FE + AD)

1440 = 1/2×h×5.47+54.6

1440×2=h×60.07

h = 1440×2/60.07

h = 47.94cm