Question

the area of trapezium is 1586cm sq and the distance between its parallel side is 26cm .if one of the parallel side is 84 cm.find the other​

Answer 1

Answer:

38cm

Step-by-step explanation:

Given :-

Area of trapezium = 1586 cm sq.

Distance between parallel side = 26 cm

One of the parallel side = 84 cm

To find :-

Other parallel side

Solution :-

Area of trapezium =  ( 1 /2 ) × ( d1 + d2 ) × height

( where d1 and d2 are the two parallel sides respectively )

Given that ,

( 1 /2 ) × ( d1 + d2 ) × height = 1586

( 1 /2 ) × ( 84 + d2 ) × 26

84 + d2 = ( 1586 × 2 ) / 26

84 + d2 = 112

d2 = 122 - 84 = 38 cm

Answer 2

Step-by-step explanation:

$\huge \pink \dag \mathbb \color{cyan}A \color{pink}N \color{orange}S \color{blue}W \color{green}E \color{gray}R \color{purple} \leadsto$

$\huge{ \boxed{ \bold{ \sf{14 \: amu}}}}$

Explanation:

✑ First, Let's explore about ATOMIC MASS :

↱ An atom consists of electrons , protons and neutrons. The mass of electron is extremely small and it is taken as a negligible mass compared to the mass of a proton or neutron. Thus , The atomic mass is defined as the sum of the number of protons and neutrons present in the nucleus of an atom of that element. If is also called atomic weight. It is denoted by A. The nucleus determines the mass of an atom, while the number of electrons determines the size of the atom of the element.

Mathematically,

Atomic mass = Number of protons + Number of neutrons

i.e $\boxed{ \sf{A = p^{ + } + n^{0}}}$

———————————————————————

✎ Now , Let's find the atomic mass of atom having 6 protons and 8 neutrons :

☞ Atomic mass = No. of protons + No. of neutrons

➵ Atomic mass = 6 + 8

➵ Atomic mass =$\boxed{ \sf{14 \: amu}}$

And we're done !

Hope I helped!

Have a wonderful day! ツ

▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁