Question

the area of trapezium is 180 cm square and it's height is 9 cm if one of the parallel sides is longer than the other by 6 cm find the sum of the two parallel sides

Answer 1

let the smaller side be of length = x cm

Then length of larger side = x+6 cm

Area=1/2 × sum of parallel sides × height

180=1/2×(x+6+x)×9

360=(2x+6)×9

40=2x+6

2x=34

x=17 cm

So, parallel sides are = 17 cm and 23 cm

Answer 2

Answer:

40 cm

Step-by-step explanation:

area of trapezium = 1/2 * sum of parallel sides * height

given,

area of trapezium = 180 cm sq

height = 9 cm

let the length of parallel side be a cm  and b cm,, where a > b

therefore,

180 cm sq = 1/2 * (a + b) * 9

180 * 2 = (a + b) * 9

360 = ( a + b ) * 9

360/9 = (a+b)

40 = a+b                             ...(i)

also given,

a is greater than b by 6 cm

i.e., a = b+6                      ...(ii)

substituting the value of a in (i)

40 = b+6+b

40 = 2b +6

40 - 6 = 2b

34 = 2b

34/2 = b

17 cm = b

a = b+6

a = 17+6 = 23 cm