the area of trapezium is 180cm square and it's height is 9cm. if one of the parallel sides is longer than the other by 6cm, find the two parallel sides
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hiii!!!
here's ur answer...
given the height of the trapezium is 9cm.
given that one of the parallel sides of the trapezium is 6cm longer than other.
let the shorter parallel side be x, therefore the longer parallel side will be x + 6.
area of the trapezium = 180cm²
==> 1/2 × h ( b1 + b2 ) = 180cm²
==> 1/2 × 9 ( x + x + 6) = 180cm²
==> 4.5 ( 2x + 6 ) = 180cm²
==> 9x + 27 = 180cm²
==> 9x = 180 - 27
==> 9x = 153
==> x = 153/9
==> x = 17cm
hence, the length of shorter parallel side = x
= 17cm
length of the longer parallel side = x + 6
= 17 + 6
= 23cm
VERIFICATION:-
area of the trapezium = 1/2×h(b1+b2)
= 1/2×9(17+23)
= 4.5×40
= 180cm²
hence verified
hope this helps u frnd..!
here's ur answer...
given the height of the trapezium is 9cm.
given that one of the parallel sides of the trapezium is 6cm longer than other.
let the shorter parallel side be x, therefore the longer parallel side will be x + 6.
area of the trapezium = 180cm²
==> 1/2 × h ( b1 + b2 ) = 180cm²
==> 1/2 × 9 ( x + x + 6) = 180cm²
==> 4.5 ( 2x + 6 ) = 180cm²
==> 9x + 27 = 180cm²
==> 9x = 180 - 27
==> 9x = 153
==> x = 153/9
==> x = 17cm
hence, the length of shorter parallel side = x
= 17cm
length of the longer parallel side = x + 6
= 17 + 6
= 23cm
VERIFICATION:-
area of the trapezium = 1/2×h(b1+b2)
= 1/2×9(17+23)
= 4.5×40
= 180cm²
hence verified
hope this helps u frnd..!
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