Math, asked by Kyushu1, 1 year ago

the area of trapezium is 180cm square and it's height is 9cm. if one of the parallel sides is longer than the other by 6cm, find the two parallel sides

Answers

Answered by Anonymous
11
hiii!!!

here's ur answer...

given the height of the trapezium is 9cm.

given that one of the parallel sides of the trapezium is 6cm longer than other.

let the shorter parallel side be x, therefore the longer parallel side will be x + 6.

area of the trapezium = 180cm²

==> 1/2 × h ( b1 + b2 ) = 180cm²

==> 1/2 × 9 ( x + x + 6) = 180cm²

==> 4.5 ( 2x + 6 ) = 180cm²

==> 9x + 27 = 180cm²

==> 9x = 180 - 27

==> 9x = 153

==> x = 153/9

==> x = 17cm

hence, the length of shorter parallel side = x

= 17cm

length of the longer parallel side = x + 6

= 17 + 6

= 23cm

VERIFICATION:-

area of the trapezium = 1/2×h(b1+b2)

= 1/2×9(17+23)

= 4.5×40

= 180cm²

hence verified

hope this helps u frnd..!
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