Question

the area of trapezium is 182 sq cm. its height is 14cm. the shorter parallel side is shorter than the other one by 16 cm. find the lengths of the parallel side

Answer 1

let the longer parallel side be x and shorter be x-16cm. then,1/2×(x+x-16)×14cm=182cm^2. (2x-16cm)×7cm=182cm^2. 2x-16cm=26cm 2x=26cm+16cm. x=42cm/2=21cm. the longer side=21cm, shorter side =21cm-16cm=5cm.

Answer 2

Hi ,
************************************
Let a and b are two parallel sides

of the trapizium,

Height between them = h

Area ( A ) = ( a+ b ) h /2
********************************"********

According to the problem given,

h = 14 cm

Shorter side = a cm

Longer side = ( a + 16 ) cm

A = 182 sq cm

[ a + a + 16 ) × 14 ] / 2 = 182

( 2a + 16 )7 = 182

2a + 16 = 182 / 7

2a = 26 - 16

2a = 10

a = 10 / 2

a = 5

Therefore ,

Length of the shorter side = a = 5 cm

Length of the longer side = a + 16

= 5 + 16

= 21 cm

I hope this helps you.

:)