the area of trapezium is 182cm^2and its height is 14cm .if o e of thr parallel sides is longer than the other by 16cm ,find the length of its parallel sides
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Area of trapezium =
Let one of the parallel sides be x cm
second parallel side = x+16 cm
height = 14cm
area = 182cm²
Substituting values in the formula,
182=[(2x+16)14]/2
2x + 16 = 26
2x = 10
x = 5cm
therefore, one of the parallel side = 5cm
second parallel side = 5+16 = 21cm.
Thanks
Let one of the parallel sides be x cm
second parallel side = x+16 cm
height = 14cm
area = 182cm²
Substituting values in the formula,
182=[(2x+16)14]/2
2x + 16 = 26
2x = 10
x = 5cm
therefore, one of the parallel side = 5cm
second parallel side = 5+16 = 21cm.
Thanks
Answered by
0
area of trapezium = 1/2 × ( Sum of two parallel side)×height
182 cm^2 = 1/2×( 16+b) × 14
182cm^2 = (8+ b)× 14
182cm^2 = 8+b× 14
182 cm^2 = 112+ b
b = 182 cm^2 -112
b= 70 cm^2
.
. . b= 70 cm^2
182 cm^2 = 1/2×( 16+b) × 14
182cm^2 = (8+ b)× 14
182cm^2 = 8+b× 14
182 cm^2 = 112+ b
b = 182 cm^2 -112
b= 70 cm^2
.
. . b= 70 cm^2
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