the area of trapezium is 216 M square and its height is 12 M . if one of the parallel sides is 14 cm less than the other , find the length of each of the parallel sides
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Solution :
Given Area of the trapezium (A)= 216m²
Let a , b are lengths of two parallel
sides,
a = x m ,
b = ( x - 14 )m
height ( h ) = 12 m
[(a+b)h]/2 = A
=> [x+x-14)12]/2 = 216
=> ( 2x - 14 )6 = 216
=> 2x - 14 = 216/6
=> 2x = 36 + 14
=> 2x = 50
=> x = 50/2
=> x = 25
Therefore ,
a = x = 25 m
b = x - 14
= 25 - 14
= 11 m
••••
Given Area of the trapezium (A)= 216m²
Let a , b are lengths of two parallel
sides,
a = x m ,
b = ( x - 14 )m
height ( h ) = 12 m
[(a+b)h]/2 = A
=> [x+x-14)12]/2 = 216
=> ( 2x - 14 )6 = 216
=> 2x - 14 = 216/6
=> 2x = 36 + 14
=> 2x = 50
=> x = 50/2
=> x = 25
Therefore ,
a = x = 25 m
b = x - 14
= 25 - 14
= 11 m
••••
Answered by
0
Answer:
yahh
a = x
h=12
X = 25
Y=11
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