Question

the area of trapezium is 248 metre square its heigth is 8 metre if one of the parrlel side is 4 metre greater then the other , find the other parrlel side

Answer 1

⇒Given:

Area of trapezium= 248 m²

Height (h)= 8 m

⇒Solution :

Let the one parallel side be= x m

Other parallel side =( x-4) m

Area of trapezium = 1/2 ( sum of parallel sides) × height

248 = 1/2 ( X+ X- 4)× 8

248 = (2x - 4) × 4

248/4 = 2x-4

62 = 2x-4

62+4= 2x

66= 2x

X= 66/2

X= 33

One parallel side (X)= 33 m

Other parallel side(x-4)= 33-4= 29 m

Answer 2

Answer:-

AREA OF TRAPEZIUM = $\frac{1}{2}$ × SUM OF ║ SIDES × ⊥ DISTANCE BETWEEN THEM

GIVEN THAT, AREA = 248 m²

HEIGHT = 8 m

Let the sides be: x , x-4

with, longer side = x

Shorter side = x - 4

Now, $248 = \frac{1}{2 } * (x+x-4) *8$

⇒ 62 = 2x - 4

→ 2x = 66

⇒ x = 33

So, the longer side is 33 m

Smaller side = x-4 = 33-4 = 29 m

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