the area of trapezium is 248 square metre and its height is it if one of the parallel side is smaller than the other by 4 m find two parallel sides
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Area of trapezium= 248 m²
Height (h)= 8 m
Let the one parallel side be= x m
Other parallel side =( x-4) m
Area of trapezium = 1/2 ( sum of parallel sides) × height
248 = 1/2 ( X+ X- 4)× 8
248 = (2x - 4) × 4
248/4 = 2x-4
62 = 2x-4
62+4= 2x
66= 2x
X= 66/2
X= 33
One parallel side (X)= 33 m
Other parallel side(x-4)= 33-4= 29 m
Height (h)= 8 m
Let the one parallel side be= x m
Other parallel side =( x-4) m
Area of trapezium = 1/2 ( sum of parallel sides) × height
248 = 1/2 ( X+ X- 4)× 8
248 = (2x - 4) × 4
248/4 = 2x-4
62 = 2x-4
62+4= 2x
66= 2x
X= 66/2
X= 33
One parallel side (X)= 33 m
Other parallel side(x-4)= 33-4= 29 m
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