The area of trapezium is 248cm² and its height is 8m.If one of the parallel sides is smaller than the other by 4m find the length of the two parallel lines...
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Given:
Area of trapezium= 248 m? Height (h)= 8 m
Let the one parallel side be= x m Other parallel side =( x-4) m
Area of trapezium = 1/2 (sum of parallel = sides) x height
248 = 1/2 (X+ X- 4)x 8
248 = (2x - 4) x 4
248/4 = 2x-4 =
62 = 2x-4
62+4= 2x
66= 2x
X= 66/2
X= 33
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