Question

the area of trapezium is 270 cm² and its height is 12cm . if one of the parallel sides is longer than the other by 5 cm, find the length of two parallel sides

Answer 1

let the parallel sides be x & x+5.

Ar. of trapezium=1/2×h×(side1 + side2)

270 = 1/2 × 12 × (x+x+5)

270 = 6×(2x+5)

270 = 12x + 30

12x 270-30

12x = 240

x = 240/12 = 20

1st parallel side = 20cm

2nd parallel side = 20+5 = 25cm

Answer 2

Answer:

Area of trapezium

A=h/2(a + b)

h = height, a=b+5

a,b, parallel sides

270 = 12/2(b+5+b)

270=6x(2b+5)

2b+5=270 / 6=45

2b +5=45

2b = 45-5=40

2b=40

b = 40/2=20

a=b+5=20+5 = 25

Parallel sides a = 25cm, b = 20cm