Question

the area of trapezium is 300m^2. the perpendicular distance between 2 parallel side is 15m . if the difference of parallel side is 16 cm, find the length of parallel sides​

Answer 1

Answer:

Question:-

The area of trapezium is 300m^2. the perpendicular distance between 2 parallel side is 15m . if the difference of parallel side is 16 cm, find the length of parallel sides

Given:-

• The area of trapezium is 300m^2
• The distance between two parallel side is 15m
• The difference of parallel side is 16cm

To find:-

The length of parallel sides

$\huge\mathfrak\purple{Solution:-}$

The distance between two parallel side is 15m so it is height

The difference of parallel side is 16cm so it us the parallel sides

Let the parallel sides be a

=a+a-16

As we know area of trapezium=

$\frac{1}{2} (sum \: of \: parallel \: sides) \times height$

On substituting the given values we get

$\frac{1}{2} (a + a - 16) \times 15 = 300$

$\mapsto \: \frac{1}{2} (2a + 16) - 15 = 300$

$\mapsto \: (2a - 16) \times 15 = 300$

$\mapsto \: 2a - 16 = \frac{300}{15}$

$\mapsto \: 2a - 16 = 40$

$\mapsto2a = 40 + 16$

$\mapsto \: 2a = 56$

$\mapsto \: a = \frac{56}{2}$

$\mapsto \: a = 28m$

The other parallel side

a=28

a-16

28-16

=12

So the two sides are 28m and 12m