Question

The area of trapezium is 336 sq. cm . If its parallel sides are in the ratio of 5:7 and the perpendicular distance between them be 14 cm , find the length of smaller one of parallel sides....?
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Answer 1

$\rm{Answer} \\ \downarrow\downarrow\downarrow\downarrow\downarrow\downarrow$

$\rm{Let \: the \: parallel \: sides \: be \: 5x \: and \: 7x}$

$\rm{Area \: of \: trapezium = \frac{1}{2} (sum \: of \: parallel \: side) \times perpendicular \: distance \: between \: them.}$

$\rm{336 = \frac{1}{ \cancel2} {}^{ {}^{} } (5x + 7x) \times \cancel{14 } {}^{7} } \\ \implies \: \rm{336 = 12 \times 7 = 84x} \\ \implies \rm{x = \frac{336}{84} = 4}$

$\rm{5x = 5 \times 4 = 20cm} \\ \rm{7 \times 4 = 28cm}$