Question

The area of trapezium is 384 cm 2. If its parallel sides are in the ratio 3:5 and the perpendicular distance between them be 12cm. Find the smallest of the parallel side.

Answer 1

Area =1/2*(sum of parellel sides) *(perpendicular distance)
Let parellel sides be 3x,5x
Therefore
384=1/2*(3x+5x)*12
768=8x*12
x=8cm
Therefore
Smallest parellel side=3x=3*8=24cm
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Answer 2

area of trapezium=384cm
parallel sides=3x , 5x
height=12cm

area of trapezium=
$\frac{d1 + d2}{2} \times h$
$\frac{3x + 5x}{2} \times 12$
$\frac{8x}{2} \times 12$
$8x \times 6$
$8x \times 6 = 384 \\ 8x = \frac{384}{6} \\ 8x = 64 \\ x = \frac{64}{8} \\ x = 8$
parallel sides,d1=8cm,d2=2cm