Question

The area of trapezium is 440 sq.m. the two parallelsides are 30 m and 14 m. Find the
distance between two parallel sides.

Answer 1

$area = 440m {}^{2} \\ \frac{1}{2} (b1 + b2)h = 440 \\ \frac{1}{2} (30 + 14)h = 440 \\ 44h = 440 \times 2 \\ h = \frac{440 \times 2}{44} \\ h = 2 \times 10 \\ h = 20m$

Hope it helps...

Please give thanks if you find my answer helpful

Answer 2

Given:-

• Length of sides of trapezium is 30 and 14 metres.
• Area of trapezium is 440² metres.

To Find:-

• Distance between their sides?

Solution:-

Area of trapezium

$\dag{ \underline{ \boxed{ \rm { \green{½ \times (a + b) \times h}}}}}$

Where,

• a and b = sides
• h = height

According to the question

$\rm→ 440 = ½ \times (30 + 14) \times h \\ \\ \rm→ 440 = ½ \times (44 ) \times h \\ \\ \rm→ 440 = 22 \times h \\ \\ \rm→ \frac{440}{22} = h \\ \\ \rm→ 20 = h$

Hence, the difference between their lengths is 12 cm.