Question

the area of trapezium is 44sq.cm and its height is 4cm. find the length of the two parallel sides if one side is shorter than the other by 2cm

Answer 1

Area of trapezium= 1/2(a+b)×h

Let one side be x
then other ll side x+2

area = 1/2 ×4 ×(x+x+2)

=2(2x+2)=44

=> 4x+4=44


=>x=10

So two ll sides are 10 and 12

Answer 2

let one side of trapezium be x and another side be (x-2)
area of trapezium=(1/2×sum of parrallel sides×height)
but area =44 square cm
BTP,
(1/2×[x+x-2]×4)=44
2x-2=22
2x=20
x=5
so the sides are 5 cm and (5-2) .i.e.3 cm