Math, asked by anitakumar15021976, 2 months ago

the area of trapezium is 475 cm ² and the heightis 19cm find the length of its two parallel sides , if one side is 4 cm greater than other​

Answers

Answered by ShírIey
57

Given: The area of trapezium is 475 cm² and the height is 19 cm.

Need to find: The length of its two parallel sides.

❒ Let the smaller side of trapezium is x cm and Larger side is (x + 4) cm.

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\qquad\boxed{\bf{\mid{\overline{\underline{\purple{\bigstar\: According \ to \ the \ Question \: :}}}}}\mid}\\\\

  • The area of the given trapezium is 475 cm².⠀

\underline{\bf{\dag} \:\mathfrak{As \: we \; know \; that\: :}}

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\star\:\boxed{\sf{\pink{Area_{\:(trapezium)} = \dfrac{1}{2} \times sum \: of \; || \; sides \times Height}}}

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Therefore,

:\implies\sf 475 = \dfrac{1}{2} \times \Big(x + (x + 4) \Big) \times 19\\\\\\:\implies\sf   475 = \dfrac{1}{2} \times \Big(2x + 4 \Big) 19 \\\\\\:\implies\sf    \dfrac{\cancel{475}}{\cancel{19}} = \dfrac{1}{2} \times \Big(2x + 4 \Big)\\\\\\:\implies\sf   25 = \dfrac{1}{2} \times \Big(2x + 4 \Big)\\\\\\:\implies\sf   50 = 2x + 4\\\\\\:\implies\sf   2x = 50 - 4\\\\\\:\implies\sf   2x = 46\\\\\\:\implies\sf   x = \cancel\dfrac{46}{2}\\\\\\:\implies{\underline{\boxed{\frak{\purple{x = 23}}}}}\:\bigstar

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Hence,

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  • Smaller side, x = 23 cm

  • Larger side, (x + 4) = (23 + 4) = 27 cm

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\therefore\:{\underline{\sf{Hence, \ the \ length \; of \: || \; sides \; of \; trapezium \: are \: \bf{23 \: cm \: and \: 27 \; cm}.}}}


spacelover123: Nice
Answered by Anonymous
94

Answer:

Given :-

  • The area of trapezium is 475 cm² and the height is 19 cm and if one side is 4 cm greater than other.

To Find :-

  • What is the length of two parallel sides.

Formula Used :-

{\red{\boxed{\small{\bold{Area\: of\: trapezium\: =\: \dfrac{1}{2} \times Sum\: of\: parallel\: sides\: \times Height}}}}}

Solution :-

Let, the smaller side be x cm

And, the greater side will be x + 4 cm

Given :

  • Area of trapezium = 475 cm²
  • Height = 19 cm

According to the question by using the formula we get,

\sf \dfrac{1}{2} \times x + x + 4 \times 19 =\: 475

\sf \dfrac{1}{2} \times 2x + 4 \times 19 =\: 475

\sf \dfrac{1}{2} \times 2x + 4 =\: \dfrac{\cancel{475}}{\cancel{19}}

\sf \dfrac{1}{2} \times 2x + 4 =\: 25

\sf 2x + 4 =\: 25 \times 2

\sf 2x + 4 =\: 50

\sf 2x =\: 50 - 4

\sf 2x =\: 46

\sf x =\: \dfrac{\cancel{46}}{\cancel{2}}

\sf\bold{\purple{x =\: 23\: cm}}

Hence, the required parallel sides are,

Smaller side = x = 23 cm

Greater side = x + 4 = 23 + 4 = 27 cm

\therefore The two parallel sides of a trapezium is 23 cm and 27 cm.


MystícPhoeníx: Keep it Up !!
spacelover123: Amazing :)
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