Question

The area of trapezium is 475 cmsq and its height is 19 cm. Find the length of its two parallel sides if one side is greater than the other

Answer 1

Given :

Area of Trapezium = 475 cmsq

height = 19 cm

Find:

Length of it's two parallel sides , if one side is greater than the other by 4 cm.

Area of Trapezium = 1/2x (a+b)xh

a+b = Length of parallel sides

475 = 1/2x(x+x+4)x19

475/19=1/2x(2x+4)

25x2/1=(2x+4)

50=2x+4

50-4=2x

46=2x

x=46/2

x=23

Hope this helps you :)

Answer 2

Answer:

i guess

your answer

area of trapezium = 475 cm sq ( given )

formula = 1/2 × ( sum of parallel side ) × height

let the parellel sides be x and 2x respectively

area= 1/2 × ( 4+x+x) × 19

=475 = 1/2 × ( 4+x + x) × 19

=475/ 19 = 1/2 × ( 4+x)

= 25 = 1/2 × 4+x

= 25 = 4+x

= 25-4 =x

= 23 = x

x = 23

x+4 = 27

hope so it helped you

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