the area of trapezium is 475 m square and the height is 19 cm find the length of the of which parallel sides if one side is 4 cm greater than the other.
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A=475 m²
h=19 cm=19/100m
Let length of one side=x
Let the length of the other side=x+4
A=1/2*(Sum of parallel sides)*Height
475=1/2*(x+x+4)*19/100
475*2*100/19=2x+4
95000/19=2x+4
5000-4=2x
4996=2x
4996/2=x
∴x=2498
Length of the first side=2498m
Length of the second side=2498+4=2502m
h=19 cm=19/100m
Let length of one side=x
Let the length of the other side=x+4
A=1/2*(Sum of parallel sides)*Height
475=1/2*(x+x+4)*19/100
475*2*100/19=2x+4
95000/19=2x+4
5000-4=2x
4996=2x
4996/2=x
∴x=2498
Length of the first side=2498m
Length of the second side=2498+4=2502m
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