Question

The area of trapezium is 476. The lengths of the parallel sides are 10cm and 46 cm. Find the distance between them

Answer 1

${\orange{\underbrace{\overbrace{\bf{ Solution :}}}}}$

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the distance between parallel sides of trapezium are height of trapezium.

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Let, the height be x

area of trapezium = ${476cm}^{2}$

1/2 × height × sum of parllel side = ${476cm}^{2}$

1/2 × x × 10cm + 46cm = ${476cm}^{2}$

1/2 × x × 56cm = ${476cm}^{2}$

1/2 × 56cmx = ${476cm}^{2}$

28cmx = ${476cm}^{2}$

x = $\frac{{476cm}^{2}}{ 28cm}$

x = $\frac{{\cancel{476cm}}^{2}}{ \cancel{28cm}}$

x = $17cm$

height of trapezium is 17cm. it means that distance between parallel side is 17cm

${\blue{\underbrace{\overbrace{\bf{ Answer : 17cm}}}}}$

Answer 2

Hint put formula in question rightly so that u can get the right answer.

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