the area of trapezium is 540sqr cm .if the ratio of parallel sides is 7:5 and the distance between them is 18 cm ,find the length of parallel sides
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1
ar of trap= 1/2 (b1 +b2) *h
540. =1/2( 7x +5x) *18
540-9 = 12x
5 3 1 = 12x
531/12 =x
44.25 =x
now put value of x in b1 and b2
540. =1/2( 7x +5x) *18
540-9 = 12x
5 3 1 = 12x
531/12 =x
44.25 =x
now put value of x in b1 and b2
Answered by
1
area of trapezium=1/2 ×h×sum of parallel sides
= 1/2 ×18×12x
540= 108x
x=5
7x=35
5x=25
= 1/2 ×18×12x
540= 108x
x=5
7x=35
5x=25
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