Question

The area of trapezium is 570 cm^2

and the height is 9.5 cm. Find the lengths of its two parallel sides if one

side is 4 cm greater than the other.​

Answer 1

Given:

area of the trapezium = 570²

height of the trapezium = 9.5cm

measure of one side is 4cm greater than other

To Find:

length of the two parallel sides

Solution:

Let the length of the smaller parallel side = x cm

then, length of the greater parallel side = (x+4)cm

We know that,

area of trapezium =$\small\sf\purple { \frac{1}{2} (sum \: of \: parallel \: sides) \times height}$

So,

$\implies \sf{\: 475 = \frac{1}{2} (x + x + 4) \times 19}$

$\implies\sf{ \: 475 = (x + 2) \times 19}$

$\implies\tt{ \: 25 = x + 2}$

$\implies\tt{ \: x = 25 - 2 = 23}$

$\implies\tt{ \: x = 23}$

$➙$smaller parallel side = $\tt\underline\red{23cm}$

Now,

greater parallel side = 23 + 4

$➙$greater parallel side = $\tt\underline\red{27cm}$

Hence:

• smaller parallel side = 23cm
• greater parallel side = 27cm