Math, asked by Mister360, 4 months ago

The area of trapezium is 60 cm^2. If the height is 4 cm. And the 1st parallel side is 19 cm. Then find the other side

Answers

Answered by TheHoneyBabe
3

Answer:

the other side = 11 cm

Step-by-step explanation:

area of trapezium= 1/2× height × (p1+p2)

=)60=1/2×4×(19+p2)

=)60×2/4=19+p2

=)30=19+p2

=)30-19=p2

=)p2=11

hope it helps you

Answered by BrainlyPhantom
9

⇒ Given:

The area of trapezium is 60 cm².

The height of the trapezium is 4 cm and one of the parallel sides is 19 cm.

⇒ To Find:

The length of the other side.

⇒ Solution:

The basic concept to be used in this question is the formula to find the area of a parallelogram.

The formula is as follows:

\sf{Area\:of\:a\:trapezium=\dfrac{a+b}{2}\times\:h}}

Here, a and b refers to parallel sides of the trapezium and h refers to the height.

Writing down the values we know:

The area of trapezium is 60 cm².

Height of the trapezium is 4 cm.

One of the parallel sides is 19 cm.

Applying the values in the equation:

\sf{=\dfrac{19+b}{2}\times4=60}

\sf{b=\dfrac{60}{4}\times2-19}

\sf{b=30-19}

\sf{b=11\:cm}

The length of the other parallel side of the trapezium is 11 cm.

⇒ Verification:

LHS of the equation:

\sf{=\dfrac{19+b}{2}\times4\:where\:b=11}

\sf{=\dfrac{19+11}{2}\times4}

\sf{=\dfrac{30}{2}\times4}

\sf{=15\times4}

\sf{=60}

RHS of the equation:

\sf{=60}

LHS = RHS

Hence verified!

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