Question

the area of trapezium is 960 sq cm if the parallel sides are 34 and 46 cm find the distance between them​

Answer 1

$\underline{\boxed{\sf{\ Area \ of \ trapezium= \dfrac{1}{2}\times (sum\ of \ parallel\ sides )\times height }}}$

Now we have ,

• Area = 960sq.cm
• parallel sides = 34 and 46 cm

★ We have to find the distance between the parallel sides which is equal to the height of the trapezium

Now by substituting the values in the formula

$\dashrightarrow\sf Area = \dfrac{1}{2}\times (sum\ of \ parallel\ sides )\times height \\ \\ \\ \dashrightarrow\sf 960= \dfrac{1}{2}\times (34+46)\times height\\ \\ \\ \dashrightarrow\sf 960\times 2 = 80\times height \\ \\ \\\dashrightarrow\sf 1920=80\times height \\ \\ \\\dashrightarrow\sf Height = \cancel{\dfrac{1920}{80}}\\ \\ \\\dashrightarrow\sf Height = {\underline{\boxed{\pink{\mathfrak 24cm}}}}$

Answer 2

Answer:

given area of trapezium are equal 960 CM square

and length of the parallel sides are 84 cm and 46

Step-by-step explanation:

area of trapezium

1

- × ( sum of The parallel sides)×( perpendicular distance b. between the parallel side)

2

960 =1/2× 34+46 ×height

960 =,40 ×h

h= 960/40=24 cm