Question

the area of trapezium of altitude 3 cm is 12m2 . if one of the parallel sides is 2m more than the other then find the lengths of parallel sides of the trapezium.

Answer 1

12 = ½*3*2+x
$\frac{12 \times 2}{3} = 2 + x$
8 - 2 = x
6 = x answer

Answer 2

PLZ MARK MY SOLUTION AS THE BRAINLIEST.

LET ONE // SIDE BE EQUAL TO X m.

SO, OTHER // SIDE = ( X + 2 )m

ALTITUDE = 3 m

SO, BY THE PROBLEM,

WE KNOW THAT THE AREA OF A TRAPEZIUM IS HALF OF THE PRODUCT OF THE ALTITUDE AND SUM OF THE // SIDES.

THEREFORE,

1/2 × ( 2X + 2 ) × 3 = 12

( X + 1 ) × 3 = 12

(BY TRANSPOSING 3 TO OTHER SIDE)

X + 1 = 12/3

X = 4 - 1

X = 3

SO THE SIDES ARE 3 m AND 5 m respectively