Math, asked by vsvejay874, 7 hours ago

The area of trapezium whose h=10 m and a=12m,b=20m is_______________.​

Answers

Answered by HemankGupta
1

Answer:

160 m^{2}

Step-by-step explanation:

Two lengths of trapezium = 12m and 20m

Height of trapezium = 10 m

Area of trapezium = \frac{1}{2} x h x (a + b)

= \frac{1}{2} x 10 x (12 + 20)

= 5 x 32

= 160 m^{2}

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Answered by yagasreeram
1

hope it helps you ☺️!!!

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