Math, asked by sagarproboy5500, 20 days ago

The area of trapezium whose height is 6 cm and sum of length of parallel sides is 20 cm is​

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Answered by nanditapsingh77
0

The area of trapezium whose height is 6 cm and sum of length of parallel sides is 20 cm is 60 cm².

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Answered by aftabahemad
0

As per the data given in the question,

We have to determine the area of trapezium.

As we know that,

$$\begin{array}{l}A=\frac{a+b}{2} h \\a \text { Base } \\b \text { Base } \\h \text { Height }\end{array}$$

So, From the question,

It is given that,

height = 6 cm

Sum of parallel sides = 20 cm

So, putting these values in above expression,

We will get the area as,

A=\frac{a+b}{2} h\\Area = \frac{20}{2}\times 6\\Area = 60\:Sq.\:cm

Hence, area of trapezium will be 60 Sq. cm

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