Question

The area of triangle 120 cm square. find the base if the measure of its corresponding altitude is 24 cm.

Answer 1

$\huge{\boxed{\tt{Answer:-10cm}}}$

$\sf\underline{\blue{\:\:\: Given:-\:\:\:}}$

$\sf\bullet Area \:of \:\triangle =120cm{}^{2}\\ \\ \sf\bullet Altitude\: of \:triangle=24cm$

$\bigstar{\boxed{\sf{Area\:of\:\triangle=\dfrac{1}{2}\times base\times height}}}$

• Now

$\sf\underline{\purple{\:\:\: SOLUTION:-\:\:\:}}$

$\sf\implies 120=\dfrac{1}{\cancel2}\times base\times \cancel{24}\\ \\ \sf\implies 120= 12\times base\\ \\ \sf\implies \cancel{\dfrac{120}{12}}=base\\ \\ \sf\implies 10=base$

$\sf\underline{Base\:of\triangle=10cm}$

Answer 2

$\huge {\red{\boxed{ \overline{ \underline{\mid\mathfrak{An}{\mathrm{sw}{ \sf{er}} \colon\mid}}}}}}$

Given :

• Area of Triangle = 120 cm²
• Height (h) = 24 cm

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To Find :

• Base of triangle

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Solution :

$\large {\boxed{\sf{Area \: = \: \dfrac{1}{2} \: \times \: Base \: \times \: Height}}} \\ \\ \implies {\sf{120 \: = \: \dfrac{1}{2} \: \times \: 24 \: \times \: Base}} \\ \\ \implies {\sf{Base \: = \: \dfrac{120 \: \times \: 2}{24}}} \\ \\ \implies {\sf{Base \: = \: \dfrac{240}{24}}} \\ \\ \implies {\sf{Base \: = \: 10 \: cm}} \\ \\ \\ \large {\sf{\underline{\therefore \: \: Base \: is \: of \: 10 \: cm}}}$