Question

The area of triangle​

Answer 1

Answer:

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Step-by-step explanation:

                       $Area\:of\:triangle=\sqrt{s(s-a)(s-b)(s-c)}$

$Area\:of\:right\:angle\:triangle[90]=\frac{1}{2}\times{base}\times{height}$

$Area\:of\:equilateral\:triangle[60]=\frac{\sqrt{3} }{4}a^{2}$

     $Area\:of\:obtuse\:triangle[120]=r^{2}sin\frac{\theta}{2}cos\frac{\theta}{2}$

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