Question

The area of triangle ABC in the figure shown here is
525 cm. Find the area of the triangle BDC​

Answer 1

Answer:

$Area \: of \: ΔBDC=315cm²</p><p>$

Step-by-step explanation:

$Area \: of \: ΔABC=525cm² \\ </p><p> \frac{1}{2} ×b×h=525 \\ </p><p> \frac{1}{2} ×BC×AE=525 \\ </p><p> \frac{1}{2} ×BC×7.5=525 \\ </p><p>\frac{1}{2} ×BC \times \frac{75}{10} =525 \\ </p><p>BC=525×2×\frac{10}{75} \\ </p><p>BC=7×2×10 \\ </p><p>BC=140cm \\ </p><p>Area \: of \: ΔBDC \\ </p><p>= \frac{1}{2} ×b×h \\ </p><p>= \frac{1}{2} ×BC×DF \\ </p><p>= \frac{1}{2} ×140×4.5 \\ </p><p>= \frac{1}{2} ×140× \frac{45}{10} \\ </p><p>=7×45 \\ </p><p>=315cm²$

Answer 2

Answer:

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