The area of triangle ABC is 15 cm sq. If ΔABC and a parallelogram ABPD are on the same base and between the same parallel lines then what is the area of parallelogram ABPD.
Answers
Given :
- Area of triangle ABC = 15 cm²
- ΔABC and a parallelogram ABPD area on the same base and between the same parallel lines.
To find :
- Area of parallelogram ABPD
Solution :
Area of parallelogram ABPD = 2 × Area of triangle ABC [∵ They are on the same base and between the same parallel lines.]
⠀⇒ Area of parallelogram ABPD = 2 × 15
⠀⇒ Area of parallelogram ABPD = 30
★ Area of parallelogram ABPD = 30 cm²
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Know More :-
Triangles :-
- A triangle has three sides, three angles.
- The sum of the angles of triangles is equal to 180°.
- The largest side of the triangle is the hypotenuse.
Formula to calculate area of triangle :-
- Area of triangle = 1/2 × base × height
Parallelogram :-
- The opposite sides of the parallelogram are equal to each other.
- If one of the angle of the parallelogram is 90° then all other angles are also 90°.
- The diagonals of a parallelogram bisect each other.
Formula to calculate area of parallelogram :-
- Area of parallelogram = base × height
Given:-
- The area of triangle ABC is 15 cm sq. If ΔABC and a parallelogram ABPD are on the same base and between the same parallel lines.
⠀
To find:-
- Area of parallelogram ABPD.
⠀
Solution:-
According to the question,
We know that,
⇛ Area of parallelogram = 2 × Area of ∆ABC
⇛ Area of parallelogram = 2 × 15
⇛ Area of parallelogram = 30 cm²
⠀
Hence,
- the area of parallelogram ABPD is 30 cm².
⠀
More Formulas:-
→ Area of rectangle = length × breadth sq.units
→ Perimeter of square = 4 × side units
→ Area of square = side × side sq.units
→ Perimeter of circle = 2πr units
→ Area of circle = πr² sq.units
→ Perimeter of parallelogram = 2 × (a + b) units
→ Area of parallelogram = base × height sq.units
→ Perimeter of rhombus = 4 × side units
→ Area of rhombus = 1/2 × diagonal (1) × diagonal (2) sq.units
→ Perimeter of equilateral triangle = 3 × side units
→ Area of equilateral triangle = √3/4 × a² = 1/2 × side × height sq.units
→ Perimeter of trapezoid = (Sum of all sides) units
→ Area of trapezoid = 1/2 × height × (sum of parallel sides) sq.units