Question

The area of triangle ABC is 15 cm sq. If ΔABC and a parallelogram ABPD are on the same base and between the same parallel lines then what is the area of parallelogram ABPD.

Answer 1

Given :

• Area of triangle ABC = 15 cm²
• ΔABC and a parallelogram ABPD area on the same base and between the same parallel lines.

To find :

• Area of parallelogram ABPD

Solution :

Area of parallelogram ABPD = 2 × Area of triangle ABC [∵ They are on the same base and between the same parallel lines.]

⠀⇒ Area of parallelogram ABPD = 2 × 15

⠀⇒ Area of parallelogram ABPD = 30

★ Area of parallelogram ABPD = 30 cm²

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Know More :-

Triangles :-

• A triangle has three sides, three angles.
• The sum of the angles of triangles is equal to 180°.
• The largest side of the triangle is the hypotenuse.

Formula to calculate area of triangle :-

• Area of triangle = 1/2 × base × height

Parallelogram :-

• The opposite sides of the parallelogram are equal to each other.
• If one of the angle of the parallelogram is 90° then all other angles are also 90°.
• The diagonals of a parallelogram bisect each other.

Formula to calculate area of parallelogram :-

• Area of parallelogram = base × height

Answer 2

Given:-

• The area of triangle ABC is 15 cm sq. If ΔABC and a parallelogram ABPD are on the same base and between the same parallel lines.

⠀

To find:-

• Area of parallelogram ABPD.

⠀

Solution:-

According to the question,

We know that,

⇛ Area of parallelogram = 2 × Area of ∆ABC

⇛ Area of parallelogram = 2 × 15

⇛ Area of parallelogram = 30 cm²

⠀

Hence,

• the area of parallelogram ABPD is 30 cm².

⠀

More Formulas:-

→ Area of rectangle = length × breadth sq.units

→ Perimeter of square = 4 × side units

→ Area of square = side × side sq.units

→ Perimeter of circle = 2πr units

→ Area of circle = πr² sq.units

→ Perimeter of parallelogram = 2 × (a + b) units

→ Area of parallelogram = base × height sq.units

→ Perimeter of rhombus = 4 × side units

→ Area of rhombus = 1/2 × diagonal (1) × diagonal (2) sq.units

→ Perimeter of equilateral triangle = 3 × side units

→ Area of equilateral triangle = √3/4 × a² = 1/2 × side × height sq.units

→ Perimeter of trapezoid = (Sum of all sides) units

→ Area of trapezoid = 1/2 × height × (sum of parallel sides) sq.units