The area of triangle ABC is 15 cm sq. If ΔABC and a parallelogram ABPD are on the same base and between the same parallel lines then what is the area of parallelogram ABPD
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area of parallelogram=2× area of triangle ABC
=2×15=30sq cm
theorem on area
hope it helps
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=2×15=30sq cm
theorem on area
hope it helps
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stay blessed
be happy nd keep happy
jeyuva04:
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Answer:
first draw the midpoint of side ad and join e to f.
now in figure abef triangle afe and trapezium abef are on same base and between same parallel lines there fore area afe is equal to area abef.
similarly area fed is equal to area fecd. add 1 and 2 and you will get the answer as ar(aef)=ar(abcd)1/2
Step-by-step explanation:
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