the area of triangle formed by straight line x+y=4
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If ax+by+c=0, then the area of the triangle formed by it is c² / (2ab)
Here, c = -4 ⇒ c² = 16
a = b = 1
Area of the triangle = 16 sq.units
Here, c = -4 ⇒ c² = 16
a = b = 1
Area of the triangle = 16 sq.units
Anonymous:
I am sorry the answer is 8 because its 16/2
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given x/4+y/4 = 1. so it's length of X and y intercepts is 4units so area of the triangle = 1/2*4*4 = 8sq. units
hence the required area is 8
hence the required area is 8
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